如图,三棱柱ABC-A1B1C1中,CA=CB,AB=A A1,∠BA A1=60°.如图,三棱柱ABC-A1B1C1中,CA=CB,AB=A A1,∠BA A1=60°.(Ⅰ)证明AB⊥A1C;(Ⅱ)若平面ABC⊥平面AA1B1B,AB=CB=2,求直线A1C与平面BB1C1C所成角的正弦值. 第二问要用传统方法解不要用空间向量
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IA1A1DABABDCDAB=AA1BAA1=60ABA1AA1=BA1A1DABDABCA=CBACBCDABCDABnbsp;ABA1DABCDA1DCDA1CDABA1CDA1C8834;A1CDABA1Cnbsp;IBC1CB1OA1OA1A1HCB1CB1HCA=CB=AB=AA1BB1C1CBC1CB1nbsp;ABA1A1B=AB=A1C1BA1C1BC1A1Onbsp;CB1A1OA1CB1BC1A1CB1A1H8834;A1CB1A1HBC1nbsp;A1HCB1BC1CB1BB1C1CA1HBB1C1CA1CHA1CBB1C1Cnbsp;ABCAA1B1BA1DABA1D... 本文来自网络，不代表爱上海立场，如若转载，请注明出处：//duanzhihua.cn/a1252254.html