爱上海后花园

急救!已知根号x,(根号f(x))/2,根号3(x大于等于0)成等差数列又数列{an}(an>0)中,a1=3,此数列的前n项和Sn(n属于N+)对所有大于1的正整数n都有Sn=f(S(n-1)).(1)求数列{an}第n+1项 (2)若根号bn 是1/(a(n+1)),1/an的等比中项,且Tn为{bn}的前n项和,求Tn

x3=fxS1=a1=3S1=3ngt;1Sn=f[Sn1]Sn=f[Sn1]=Sn13Sn1xSnSn=n3Sn=32an=6n3an1=6n3bn=1[anan1]=192n12n1=2182n12n1=2n12n1182n12n1=1[182n1]1[182n1]18bn=12n112n118bn1=12n312n118b2=131518b1=111318Tn=18[b1b2bn1bn]=112n1=2n2n1Tn=118n9...

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