爱上海后花园

用洛必达法则求lim(x->0)ln(1+x^2)\(secx-cosx),

limxgt;0ln1x^2secxcosx=limxgt;0ln1x^21cosxcosx=limxgt;0ln1x^2cosx1cosx^2=limxgt;0ln1x^2cosxsinx^2=limxgt;0x^2cosxx^2=1=limxgt;0ln1x^2cosxsinx^2limxgt;0ln1x^2sinx^2limxgt;0cosxlimxgt;0[2x1x^2]2sinxcosx1=limxgt;02x2sinxlimxgt;01[1x^2cosx]=1...

本文来自网络,不代表爱上海立场,如若转载,请注明出处://duanzhihua.cn/a1167036.html