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已知等差数列{an}的首项A1=3,2An=Sn·Sn-1(n>=2),求通项公式.已知等差数列{An}的首项A1=3,2An=Sn·Sn-1(n>=2),求{An}的通项公式.

2an=SnSn12SnSn1=SnSn12Sn12Sn=11Sn1Sn1=121Sn121Sn=1S1n12Sn=653nSn1=683n...

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