爱上海后花园

\已知等差数列{an}的各项均为正数,a1=3,前n项和为Sn,{bn}为等比数列,b1=2,且b2S2=32,b3S3=120.求数列{anbn}的前n项和Tn

b2S2=b2a1a2=b1q2a1d=32b3S3=b3a1a2a3=b1q178;3a13d=120d=2q=2an=a1dn1=2n1bn=b1q^n1=2^nTn=3252^22n12^n2tn=32^252^32n12^n1Tn=n12^n22^n12=2n12^n12...

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